0.185t^2-36.11t+1600=0

Solution for 0.185t^2-36.11t+1600=0 equation:

0.185t^2-36.11t+1600=0

a = 0.185; b = -36.11; c = +1600;
Δ = b2-4ac
Δ = -36.112-4·0.185·1600
Δ = 119.9321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36.11)-\sqrt{119.9321}}{2*0.185}=\frac{36.11-\sqrt{119.9321}}{0.37}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36.11)+\sqrt{119.9321}}{2*0.185}=\frac{36.11+\sqrt{119.9321}}{0.37}
$